Assumption Diameter of DNA B is 20 Angstroms
- 2.56 cm or 2.56E8 Ang for both the 1:1 and 1:1.56 CG and AT
Area of base/circle = pi(r^2) or 314 Angstorms^2
Base*Height = 2.56E8 * 314 = 8.04E10 Angstroms^3
This should then equal the (4/3)pi[r^3] volume equation of a sphere because we are going to scrunch this tube's volume into a sphere
Mind you this is different than wrapping the tube into a sphere (which is way out of my mathematical league)
Anyways, (4/3)pi[r^3] = 8.04E10 Angstroms^3
3 (root) 1.92E10 = 2.67E3 Angstroms
This is the radius but we need the diameter to compare this with the diameter of a typical cell (1E-6)
2 X 2.67E3 = 5.34E3 Angstroms = 5.34E-7 Meters
Divide the 5.34E-7 by 1E-6 = 0.534
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