Enediol Rearrangement
Carbohydrates - back
Base catalyzed unfavorable reactions of sugars
Attacks aldoses
Enediol Rearrangement
- ---C1OH-------------------------H-C1-OH
- H-C2-OH <--(NaOH/H2O)--> C2=O
Mechanism:
- OH nucleophile attacks the acidic alpha proton from the carbonyl
- The remaining electrons forms an enolate intermediate (carbanion and enolate)
- The point where it loses its stereochemistry = C2 is no longer asymmetric
- Enolate oxygen attacks a proton from water
- Regenerates the base
- Formation of the ENEDIOL
- OH nucleophile attacks the alcohol
- Enolate oxygen nucleophile attacks C2
- WHILE
- Resonance forces the enolate double bond to attack a proton from water
- Regenerates a carbonyl in the C2
- Regenerate the base
Base Catalyzation Fundamentals:
- Base catalysis occurs the same way attacking the acidic alpha proton (C2 proton)
- The deviation in the products occurs form the enolate oxygen
- -1 Reform the carbonyl from attacking the carbon it is attached to
- RESULTING IN ENOLATE PRODUCTION
- -2 Reduced to an alcohol from attacking a proton from water
- RESULTING IN ENEDIOL PRODUCTION
- Under strong basic conditions a combination of enediol and epimerization leads to complex mixture of sugars
Concepts:
Salient Examples:
Terminology:
Additional Information:
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